Math, asked by prabhupada1, 1 year ago

the ages of two persons differ by 20yr. if five yrs ago the elder one be five times as old as the younger one ,what are their present ages

Answers

Answered by Anonymous
2
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Answered by 5Vivek
1
age of younger one = x
age of elder one = x +20 (A.T.Q.)
now
5years ago,
age of younger one = x - 5
age of elder one = (x+20) - 5 = x + 15
now A.T.Q. elder one is 5 time as old as the younger one
writing this in equation
we get
x + 15 = 5(x - 5)
x + 15 = 5x - 25
4x = 40
x= 10
so
age of younger one is 10
and age of elder one is = x +20 = 10 + 20 = 30.

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