Physics, asked by shubhamnaryaal28, 3 months ago

The air vessel of a torpedo is of 50 cm external diameter, and 1 cm thickness, and length being 1.8m. Find the change in external diameter, and length when changed to 10 MN/m2 internal pressure. Take E=200×109 N/m2, Poisson’s ratio, ν=0.3.

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Answered by aryannaincy

0

Answer:

ratio" (and any subsequent words) was ignored because we limit queries to 32 words.

Explanation:

please mark me as brainest.

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