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) The algebraic expression of a sequence is xn-6n + 13n - 7 Is it an arithmetic sequence?​

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Answered by Anonymous
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The algebraic exp

Class 10th

Kerala Board Mathematics Part-1

1. Arithmetic Sequences

Answer

For it to be an AP, xn+1 – xn = constant

xn+1-xn = {(n+1)3-6(n+1)2+13(n+1)-7}-{ n3 – 6n2+ 13n – 7}

= (n+1)3-n3-6{(n+1)2-n2}+13(n+1-n)-7+7

= (n+1-n)(n2+2n+1+n2+n+n2)-6(2n+1)+13

= 1× (3n2+3n+1)-12n+7

= 3n2-9n+8

Step-by-step explanation:

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