Question

the algebraic expression of an arithmetic sequence is 4n+1. write down the first 3 terms of the sequence. is 101 a term is the sequence? ​

Answer 1

Step-by-step explanation:

let n=1

4(1)+1 = 5

let n=2

4(2)+1 = 9

let n=3

4(3)+1 = 13

hence, sequence formed is 5,9,13,....

a=5 and d=4

An= a+(n-1)d

101 = 5+(n-1)4

n=25

Since n is a natural number, 101 is a term of the sequence.