Question

the algebraic expression of px x2-2x is a quadratic polynomial reason the zero of polynomial x2-2x is 2​

Answer 1

Answer:

Let f(x) = x2 ˗ 2x ˗ 8

= x2 ˗ 4x + 2x ˗ 8

= x(x ˗ 4) + 2(x ˗ 4)

= (x ˗ 4) (x + 2)

To find the zeroes, set f(x) = 0,

then either (x ˗ 4) = 0 or (x+2) = 0 x = 4 or x = -2

Again, Sum of zeroes = (4 – 2) = 2 = 2/1 = -b/a = (-Coefficient of x)/(Coefficient of x2)

Product of zeroes = (4) (-2) = -8/1 = c/a = Constant term / Coefficient of x2