The algebraic form of an AP is 8n-4 prove that the sum of n terms of this sequence is a perfect square
Answers
Answered by
0
ANSWER
Given, arithmetic sequence X
n
=5n+3
a. The first term of the sequence, put n=1
X
1
=5×1+3=8
b. d=5 (coefficient of n be the common difference)
The remainder divide by 5=3.
(
5
8
=3,
5
13
=3,
5
18
=3,etc)
Answered by
0
Answer:
50
Step-by-step explanation:
The given AP is 3, 8,13,18....
Here, a = 3 and d = 8 – 3 = 5
∴ a30 – a20
=[3 + (30 – 1)5]- [3 + (20 – 1)5]
= 148 – 98 = 50
Thus, the required value is 50
Similar questions