Question

The algebraic form of an arithmetic sequence is 4 n+1 .

a) What is its common difference ?

b) What is its first term ?

c) What is the remainder when each term of this sequence is divided by 4 ?​

Answer 1

4n +1

Putting n as 1

a1 = 4+1=5

Putting n as 2

a2=9

Therefore common diff is = 9-5=4

remainder is 1 when each term is divided

Conclusion

a). 4

b). 5

c). 1

Answer 2

Answer:

first term is (n=1) =(4 )n+1= 4×1+1=5

second term is (n=2) =4n+1=4×2+1=9

then third term is 13

so common difference is 13-9=9-5=4

if each term is divided by 4 ;(5÷4) remainder is 1

9÷4;remainder is 1

so if each term is divided by 4 then remainder is 1