Question

the algebraic form of an as 4n+1 what is the sum of first 25 terms
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Answer 1

Answer:

17

Step-by-step explanation:

The general form is 4n+1

Let n=1,2,3,4……

Therefore, The first 4 terms are,

A1= 4(1)+1 = 4+1 =5

A2= 4(2)+1 =9

A3= 4(3)+1 =13

A4= 4(4)+1 =17.

:)

Answer 2

Step-by-step explanation:

first term a= 1

last term l= 101

common differences d= 4

sum of 25 terms = 1275

$sum \: of \: n \: terms = \frac{n}{2} (a + l) \\ = \frac{25}{2} (1 + 101) \\ = \frac{25}{2} \times 102 \\ = 25 \times 51 \\ = 1275$

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