The algebraic from of sum of an Arithmetic Sequence is n raised 2+ 2n.
a) Write the sequence.
b) What is the sum of first 10 terms
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Step-by-step explanation:
Rule for the sum of arithmetic sequence=n²+2 n
As we know sum of n terms of an Arithmetic sequence is \frac{n}{2}[2 a+(n-1)d]
2
n
[2a+(n−1)d]
⇒n²+2 n=\frac{n}{2}[2 a+(n-1)d]
2
n
[2a+(n−1)d]
⇒2(n+2)=2 a+ (n-1) d
⇒2 n + 4=2 a-d + n d
Equating LHS and RHS
⇒2 n = n d and 2 a -d= 4
⇒ d=2 ∧ 2 a- 2=4
⇒2 a= 6
⇒a=3
a). Sum of first 10 term of this sequence, put n=10 in S_{n}S
n
S_{n}S
n
= n²+ 2 n=10²+2×10=100+20=120
(b) Let p terms are needed to get the sum 168.
⇒p²+ 2 p=168
⇒p²+ 2 p-168=0
⇒(p+14)(p-12)=0
⇒p≠ -14[ number of terms can't be negative]
So, p=12
Is this correct so mark me brainliest
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