Question

The alkene R – CH = CH₂ reacts readily with B₂H6 and
formed the product B which on oxidation with alkaline
hydrogen peroxide produces
(a) R – CH₂ – CHO (b) R – CH₂ – CH₂ – OH
(c) R – C = O (d) R – CH – CH₂
| | |
CH₃ OH OH

Answer 1

The product B which on oxidation with alkaline  hydrogen peroxide produces R−CH  2 CH  2  OH.

Option (B) is correct.

Explanation:

Alkenes, when treated with di-borane gives, alkyl boranes and alkyl boranes on the oxidation with alkaline Hydrogen peroxide gives alcohols.

For propene, the mechanism is:

6CH  3 CH = H2  + (BH3  )  2  → 2(CH3 CH2 CH  2 )3  B + H2O 2 / OH  −  → 6 CH  3 CH  2 CH2 OH  

So product is R−CH  2 CH2 OH.

R is an alkyl group.

Thus the product B which on oxidation with alkaline  hydrogen peroxide produces R−CH  2 CH  2  OH.

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