The allele for a widow's peak has complete dominance over the allele for a straight hairline (w). What is the probability of two parents heterogeneous for a widow's peak (Ww) having an offspring without a widow's peak?
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The ratio by punnet square will be:
1 : 2 : 1
(WW : We : ww)
so the %age will be 25%
1 : 2 : 1
(WW : We : ww)
so the %age will be 25%
Answered by
4
Answer:
Genotype for widow's peak of both male and female is same i.e. heterozygous dominant (Ww).
Gametes formed by male = W and w,
and that of female = W and w
Cross would result in the formation of WW, Ww, and ww in 1 : 2 : 1.
One out of four carries homozygous recessive trait i.e. ww or straight hairline.
Hence, the probability of offspring without widow's peak is 1/4 or 0.25.
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