Question

The allelic frequency of recessive allele is 0.4. find out the number of heterozygous individual in a population of 500

Answer 1

Answer:

p=0.6

q=0.4

2pq=0.48

0.48×500=240

Answer 2

We are given q= 0.4

And we know that p+ q = 1

Therefore....p = 0.6

Now for heterozygous individuals

2pq = 2*0.6*0.4

= 0.48

No. Of heterozygous individuals =

0.48*500

= 240

Hope you understand.. :)