Question

the altitude and base of a triangle 4 cm and 2 cm respectively , then area will be?​

Answer 1

Question ::-

The altitude and base of a traingle 4cm and 2cm respectively then area will be ?

Given ::-

• Altitude of triangle = 4 cm.

• Base of triangle = 2 cm.

To find ::-

• Area of triangle ?

Formula used ::-

Area = $\dfrac{1}{2}$ × base × altitude

Solution ::-

Area = $\dfrac{1}{2}$ × base × altitude

Area = $\dfrac{1}{2}$ × 2 × 4

Area = $\dfrac{1}{2}$ × 8

Area = 4 ${cm}^{2}$

_________

Area of triangle , when sides are given::-

$= \: \: \: \sqrt{(s - a)(s - b)(s - c)}$

Where , s =

s = $\dfrac{a+b+c}{2}$

• s is the semi- perimeter of triangle.

Answer 2

Answer:

area of the triangle is

1/2*base*altitude

=1/2*4*2sq cm

=4sq cm