The altitude and base of a triangle having area 600sq. Cm are in the ratio 25®3 find altitude and base
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Let the common multiple be x.
Then,
Altitude=25x.
Base=3x.
Area of triangle=1/2*base*height
Here,Altitude is the height.
600= 1/2*25x*3x
600=1/2*75x^2
600=75x^2/2
75x^2=1200
x=4.
altitude=25x=100cm
Base=3x=12cm
Hope it helps you!!Please mark as brainliest!!
Then,
Altitude=25x.
Base=3x.
Area of triangle=1/2*base*height
Here,Altitude is the height.
600= 1/2*25x*3x
600=1/2*75x^2
600=75x^2/2
75x^2=1200
x=4.
altitude=25x=100cm
Base=3x=12cm
Hope it helps you!!Please mark as brainliest!!
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