the altitude and base of triangle having area 600 sq. cm are in the ratio 25:3.find altitude and base
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area of triangle =1/2*b*h
600=1/2*25x*3x
600=1/2*75x
600*2=75x
1200=75x
there fore x=16
16=ans
600=1/2*25x*3x
600=1/2*75x
600*2=75x
1200=75x
there fore x=16
16=ans
sonupndat:
altitude 100 and base 12
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