Question

The altitude and the base of a right angle triangle are 16 m & 8 m. Find the area of the triangle.​

Answer 1

Answer:

64

Step-by-step explanation:

area =1/2×base×height

=1/2×8×16

=64 m^2

Answer 2

Given :-

• The altitude of a triangle = 16m

• The base of the triangle = 8m

Solution :-

As we know that,

Area of triangle = 1/2 * base * height

Here,

Base = 8m and Height = 16m

Therefore,

Area of triangle = 1/2 * b * h

Put the required values,

Area of triangle = 1/2 * 8 * 16

Area of triangle = 4 * 16

Area of triangle = 64m^2

Hence, The Area of triangle = 64m^2

Related formulas :-

• Perimeter of triangle = 3 * side

• Area of rectangle = length * breath

• perimeter of rectangle = 2( l + b)

• Area of square = side * side

• Perimeter of square = 4 * side $.$