the altitude and the base of trangal having area 600 sq. cm are in the ratio 25:3 find the altitude and base
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Let the common ratio between the altitude and the base be=x
Altitude=25x
Base=3x
Area of a triangle= 1/2×base×height(altitude)
600 cm^2=1/2×25x×3x cm^2
75x^2=600×2=1200
x^2=1200/75=16
x=root16=4
Altitude=25×4=100cm
Base=3×4=12cm
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