Question

The altitude drawn to the base of an isosceles triangle is 8 cm and its perimeter is 64 cm. The area (in cm2) of the triangle is

Answer 1

Let, two equal sides be a.
Then, length of base will be, (64-2a).
Then, the right triangle drawn by consisting the altitude whose length is 8:
Use, Pythagoras Theorem to find a.
then, simply apply area =1/2.b.h
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Answer 2

GIVEN:-

b=12cm

area=${48cm^2}$

TO FIND:-

h=?

solution:-

WE KNOW THE AREA OF TRIANGLE AS

$= > \frac{1}{2} \times b \times h$

now, put the given values.....

$\frac{1}{2} \times 12 \times h = {48cm}^{2}$

$= > \frac{1}{ \cancel2} \times \cancel{12} \times h = 48$

$= > 6 \times h = 48$

$= > h = \frac{ \cancel{48}}{ \cancel 6}$

$= > h = 8cm$

so, the height is

$\boxed{8cm}$