The altitude drawn to the base ofan isosceles triangle is 8 cm and perimeter is 64 cm.The area of triangle is
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let the equal sides of triangle is x cm
so base of triangle is (64-2x) cm
thus area of triangle= 1/2×base×height
= 1/2 × (64-2x) × 8
= (256-8x) cm^2
so base of triangle is (64-2x) cm
thus area of triangle= 1/2×base×height
= 1/2 × (64-2x) × 8
= (256-8x) cm^2
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