Question

• The altitude of a parallelogram is one third of its base. If the area of parallelogram is 588 meter²
find its base and altitude.​

Answer 1

$\huge\bf{Answer:-}$

Let the base be x

=> x / 3 = height

=> 580cm² = area of parallelogram

=> b × h= 508 cm²

=> x × x / 3 = 508

=> x² = 508 × 3

=> x = √1534

=> x = 39.1663120551

Answer 2

Answer:let length of base be x meter. Then its height =one third of x meter

Area of parallelogram =b×h

588sq.m=x×x/3

3×588=x2

X=root 3×588

X=42m

Therefore,base=42m and height =14m

Step-by-step explanation: