the altitude of a parallelogram is one third of the base if its area is 243 CM square then its altitude is
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let the base be x
altitude will be x/3
area of parallelogram =base×altitude
a/q
base×altitude=243 sq. cm
x×x/3=243
x×x=243×3
x^2=729
x=√729
x=27
verifying
x×x/3=243
27×27/3=243
27×9=243
243=243
verified
altitude will be x/3
area of parallelogram =base×altitude
a/q
base×altitude=243 sq. cm
x×x/3=243
x×x=243×3
x^2=729
x=√729
x=27
verifying
x×x/3=243
27×27/3=243
27×9=243
243=243
verified
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