Question

The altitude of a parallelogram is twice of the length of the base and its area 900cm2.The lengths of base and altitude respectively are

Answer 1

h = 2b
area = 900 cm2 = base × height
900 = b × h
900 = b × 2b
900 = 2b^2
b^2 = 450
b = 15√2 (answer)

Answer 2

The lengths of base and altitude respectively are 21.21 cm and 42.42 cm

Step-by-step explanation:

Let the length of base be x

The altitude of a parallelogram is twice of the length of the base

So, Altitude = 2x

Area of parallelogram = $Base \times Height = x \times 2x$

We are given  its area 900 sq.cm.

So, $x \times 2x= 900$

$2x^2=900$

$x^2=450$

$x=\sqrt{450}$

x=21.21

Base = 21.21 cm

Height = 2x = 2(21.21)=42.42 cm

Hence The lengths of base and altitude respectively are 21.21 cm and 42.42 cm

#Learn more;

If the base and height of the parallelogram are in the ratio 7:3 and the height of the parallelogram is 45cm then find the area of the parallelogram

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