Math, asked by istuti, 1 year ago

the altitude of a parallelogram is twice the length of the base and its area is 1250 cm^2 . find the lengths of the base and the altitude respectively?

Answers

Answered by Rolin
18
Let the base be x and height be 2x
Area = 1250cm^2
bh = 1250cm^2
x X 2x = 1250cm^2
2x^2 = 1250cm^2
x^2 = 1250 / 2 = 625cm^2
x = √625 =25cm
Length = x = 25cm
Height = 2x = 2 X 25 = 50cm
Answered by IDJ
17
Area of a parallelogram = bh
Given height = 2*base
therefore
1250 = x * 2x
1250 = 2x²
1250/2 = x²
625 = x²
 \sqrt{625}  = 25
therefore
base = 25cm
height/altitude= 2*25=50cm
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