Math, asked by Sahil1231, 11 months ago

the altitude of a rectangle is 20% less than the base and perimeter is 18 cm. find the dimensions of the rectangle.

Answers

Answered by FelisFelis
0

Answer:

The dimension of the rectangle is: L = 4 cm and B = 5 cm.

Step-by-step explanation:

Consider the provided information.

Let the base of the rectangle is B.

As it is given that the altitude of the rectangle is 20% less than the base, this can be written as:

L = B - 20%B

L = B - 0.2B (∴ 20/100 = 0.2)

L = 0.8B

The perimeter is 18 cm.

The perimeter of the rectangle is: 2(L+B)

Substitute L = 0.8B in above formula.

2 (0.8B + B) = 18

(1.8B) = 9

B = 9/1.8

B = 5

Hence, the base is 5 cm long.

The altitude of rectangle is L = 0.8B

L = 0.8 (5)

L = 4 cm

Hence, the dimension of the rectangle is: L = 4 cm and B = 5 cm.

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