Question

The altitude of a right angle triangle is 7cm less than its base. If the
hypoteneous 13 c.m., find other sides.​

Answer 1

Answer:

ANSWER

Let x be the base of the triangle, then the altitude will be (x−7).

By Pythagoras theorem,

x

2

+(x−7)

2

=(13)

2

2x

2

−14x+49−169=0

2x

2

−14x−120=0

x

2

−7x−60=0

x

2

−12x+5x−60=0

(x−12)(x+5)=0

x=12,x=−5

Since the side of the triangle cannot be negative, so the base of the triangle is 12cm and the altitude of the triangle will be 12−7=5cm.