Question

the altitude of a right angled triangle is 7 cm less than its base. If the hypotenuse is 13 cm find the other two sides. ​

Answer 1

Answer:

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Step-by-step explanation:

Let the base =   x cm

Given that The altitude of a right triangle is 7 cm less than its baseAltitude is =   x - 7 cmGiven that hypotenuse = 13cm

Applying Pythagoras theorem,    base2+ altitude2 = hypotenuse2plug the values  we get       x2+ (  x – 7)2 = 132    x2+   x2+ 49 – 14  x = 169    2  x2 – 14  x + 48 – 169 = 0    2  x2 – 14  x  – 120 = 0Divide   by 2 to both side to simplify it    x2 – 7  x  – 60 = 0      x2 – 12  x + 5  x – 60 = 0      x (  x – 12) + 5 (  x – 12) = 0    (  x – 12)(  x + 5) = 0    x – 12 = 0 or   x + 5 = 0    x = 12 or   x = –5length can not negative so that x can not equal to – 5base     x = 12cm altitude = 12 – 7 = 5cm

Answer 2

Answer:

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