The altitude of a right triangle is 5 more than its base. If the hypotenuse is 25 cm find the other two sides of the triangle
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base=15 cm, altitude=20 cm
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let the altitude and the base of the triangle be x+5 and x
Using pythagores theorem
(x+5)^2+(x)^2 = (25)^2
x^2++5^2+x^2 = 625
x^2+25+x^2 = 625
2x^2 = 625-25
2x^2 = 600
4x^2 = 600
4x = root under 600
4x = 30
x = 30/4
x = 7.5
hence the altitude and the base of the triangle is 12.5cm and 7.5cm
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