The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
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Answer:
base = 12 cm , altitude = 5 cm
Step-by-step explanation:
Let the base of right
triangle = x cm
Altitude of the triangle = (x-7)cm
Hypotenuse = 13 cm ( given )
By Phythogarian theorem,
(Hypotenuse)² = (base)²+(altitude)²
=> ( 13 )² = x² + ( x - 7 )²
=> 169 = x² + x² - 2.x.7 + 7²
=> 169 = 2x² - 14x + 49
=> 169 - 49 = 2x² - 14x
=> 120 = 2x² - 14x
Divide each term by 2 , we get
=> 60 = x² - 7x
=> x² - 7x - 60 = 0
=> x² - 12x + 5x - 60 = 0
=> x( x - 12 ) + 5 ( x - 12 ) = 0
=> ( x - 12 )( x + 5 ) = 0
x - 12 = 0 or x + 5 = 0
x = 12 or x = -5
x should not be negative.
Therefore ,
x = 12
Now ,
Base of the triangle = x = 12 cm
Altitude = ( x - 7 )
= 12 -. 7
= 5 cm
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