the altitude of a right triangle is 7cm less than its base. if the hypotenuse is 13cm ,find the other two sides
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base=x
altitude=x-7
hypotenuse=13
therefore
13^2 = x^2 + (x-7)^2
169=x^2 + x^2 + 49
169-49=x^2/x^2
x=120cm
120-7=113cm
so base=120cm
and the altitude=113cm
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2
here is ur answer mate...........
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