The altitude of a right triangle is 7cm less than its base.if the hypotenuse is 13cm ,find the other two sides
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Let x be the base of the triangle.
Then height (which is 7 less than base) = x-7.
If the hypotenuse is 13cm, then the triangle is a right angle triangle, and we will apply Pythagoras Theorem here.
If a = base = x, b = height = x-7 and c = hypotenuse = 13, then
a^2 + b^2 = c^2. Substituting the values of a, b and c in the equation we get
x^2 + (x-7)^2 = 13^2
x^2+x^2-14x+49 = 169
2x^2-14x-120 = 0
x = (14±sqrt(14^2+4*2*120))/4
x = (14±sqrt(196+960))/4 = (14±sqrt(1156))/4 = (14±34)/4
Therefore x = 48/4 or -20/4 = 12 or -5
Since x cannot be negative, it is 12.
Thus if base = 12, then height = base - 7 = 12-7 = 5.
Therefore, base = 12cm and height = 5cm.
Then height (which is 7 less than base) = x-7.
If the hypotenuse is 13cm, then the triangle is a right angle triangle, and we will apply Pythagoras Theorem here.
If a = base = x, b = height = x-7 and c = hypotenuse = 13, then
a^2 + b^2 = c^2. Substituting the values of a, b and c in the equation we get
x^2 + (x-7)^2 = 13^2
x^2+x^2-14x+49 = 169
2x^2-14x-120 = 0
x = (14±sqrt(14^2+4*2*120))/4
x = (14±sqrt(196+960))/4 = (14±sqrt(1156))/4 = (14±34)/4
Therefore x = 48/4 or -20/4 = 12 or -5
Since x cannot be negative, it is 12.
Thus if base = 12, then height = base - 7 = 12-7 = 5.
Therefore, base = 12cm and height = 5cm.
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here is ur answer mate.......,.
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