the altitude of a right triangle is 8more then it base .if the hypotenuse is 40cm then find the length of base.
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Let x be the base of the triangle, then the altitude will be (x−7).
By Pythagoras theorem,
x²+(x−7) =(13)²
2x² −14x+49−169=0
2x²-14x−120=0
x² −7x−60=0
x² −12x+5x−60=0
(x−12)(x+5)=0
x=12,x=−5
Since the side of the triangle cannot be negative, so the base of the triangle is 12cm and the altitude of the triangle will be 12−7=5cm.
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