Question

the altitude of a triangle is 6 CM greater than its base if the area of the triangle is 108 cm² find its base and altitude?

Answer 1

Answer:

given :- altitude = 6 cm

base = ? & area = 108 cm^2

area of trangle = 1/2 × b × h

108 = 1/2 × b × 6

108 = b × 3

108/3 = b

b = 108/3

b = 36

base of a given trangle = 36 cm

Answer 2

base= 12 

FORMULA.. area=1/2[base x height] 
solution: 
height = 6 + x 
base = x 

1/2[(x)(6+x)]=108 
1/2[6x + x^2]=108 
6X + x^2 = 216 
x^2 + 6x -216=0 
(x+18)(x-12)=0 
x=(-18) or x=12 

x = base 
base = 12

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