The altitude of a triangle is 6 cm greater than its base if the area of the triangle is 108 cm aq find its vase and altitude
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ATQ, the altitude of the triangle is 6cm greater than it's base.
let the base of the triangle be x.
therefore it's altitude = x + 6
given the area of the triangle = 108cm²
➡ 1/2 × b × h = 108cm²
➡ 1/2 × x × (x + 6) = 108cm²
➡ x(x + 6) = 108 × 2
➡ x² + 6x = 216
➡ x² + 6x - 216 = 0
➡ x² + (18x - 12x) - 216 = 0
➡ x² + 18x - 12x - 216 = 0
➡ x(x + 18) - 12(x + 18) = 0
➡ (x + 18) (x - 12) = 0
therefore x = -18 or x = 12
since, base can't be in negative. so the base is 12cm.
and it's altitude = x + 6 = 12 + 6 = 18cm
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