Question

the altitude of a triangle is 7cm less then its base . if the hypotenuse is 13cm , find the two other sides

Answer 1

H^2=P^2+B^2
13^2=(B-7)^2+B^2
169=B^2+49-14B+B^2
169=49-14B+B^2
169-49=-14B+B^2
120=-14B+B^2
B^2-14B-120=0
B^2-20B+6B-120=0
(B+6)(B-20)=0
B=20cm
P=20-7
=13cm