The altitude of a triangle is five- thirds the length of its corresponding base. If the altitude is increased by 15 cm and the base decreased by 8 cm, the area of the triangle would remain the same. Find the base and altitude of the triangle??.
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Let the length of corresponding base be x.
Thus, altitude will be
3
5
x.
Now, it is given that altitude is increased by 4 cm i.e.,
3
5
x+4 and base is decreased by 2 cm i.e., x−2.
The area is same for both.
Therefore,
2
1
×x×
3
5
x=
2
1
×(
3
5
x+4)×(x−2)
⇒
3
5
x
2
=
3
5
x
2
−
3
10
x+4x−8
⇒8=
3
2
x
⇒x=12
Thus, length of base is 12 cm
and length of altitude is
3
5
×12=20 cm.
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