Question

the altitude of a triangle is three - fifth of the length of the corresponding base . if the altitude is decreased by 4 cm and the corresponding base is increased by 10 cm , the area of triangle remains the same. find the base and the altitude of the triangle
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Answer 1

Answer:

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Answer 2

Answer:

area= 1/2×base× altitude

let base be x

altitude= 3x/5

area= 1/2× x × 3x/5

3x²/10

now if, altitude= 3x/5-4

= 3x-20/5

and base =x+10

then area is same that is 3x²/10

therefore, 1/2× (x+10)×(3x-20)/5 = 3x²/10

= 1/2 × 3x² +30x -20x-200/5

3x²+10x-200/10 = 3x²/10

by cross multiply (10 on both sides will get cancel)

3x²+10x-200=3x²

10x-200=0

10x=200

x=200/10

x=20

base=x=20m

altitude=3x/5= 3×20/5 =12m.