the altitude of a triangle is two third the length of its corresponding base .if the altitude is increased by 4cm and the base is decreased by 2cm ,the area of the triangle remains the same .find the base and altitude of triangle
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Answer:
let the base=xcm
altitude=2/3xcm
area of triangle=1/2×base×height
=1/2×x×2/3x
=1/2×2/3x²cm²(1)
area=1/2(x-2)(2x+12/3)_(2)
1÷2×2÷3x²=1÷2(x-2)(2x+12÷3)
2x²=1÷2(x-2)(2x+12÷3)×2×3
2x²=(x-2)(2x+12)
2x²=2x²+12x-4x-24
2x²=2x²+8x-24
2x²-2x²-8x=-24
-8x=-24
x=24÷8
=3
so,base=3cm
and,altitude=2/3x
=2/3×3
=2cm.
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