The altitude of a triangle is two-third the length
of its corresponding base. If the attitude increased
by 4 cm and the base decreased by 2 cm, the area
of the triangle remains the same. Find the base
and the altitude of the triangle.
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Answer: 2
Step-by-step explanation:
Let x be the base. Altitude is 2x/3.
Area = 0.5(x*2x/3) = x²/3
Now let new base and height be x-2 and 2x/3 + 4.
Area = 0.5(x-2)(2x/3 + 4) = 2x²/3 + 8x/3 -8
Since areas are same,
x²/3 =x²/3 + 4x/3 -4
Solving we get x = 3
Therefore altitude = (2/3).3= 2
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