Question

The altitude of a triangle is two-third the length
of its corresponding base. If the attitude increased
by 4 cm and the base decreased by 2 cm, the area
of the triangle remains the same. Find the base
and the altitude of the triangle.​

Answer 1

Answer:

Let base be x and height be y.

now

height is two - third of the base

$= > y = \frac{2}{3} x$

Then area of triangle =

$\frac{1}{2} \times x \times y$

According to next condition

Base = x - 2

Height = y + 4

Area of triangle =

$\frac{1}{2} (y + 4)(x - 2)$

Now,

$\frac{1}{2} xy = \frac{1}{2} (x - 2)(y + 4) \\ xy = xy + 4x - 2y - 8 \\ \\ 4x - 2y = 8 \\ 4x - 2( \frac{2}{3} x) = 8 \\ 6x - 4x = 24 \\ 2x = 24 \\ x = 12 \\ and \: y \: = 8$

Answer 2

Answer:

sorry I haven't the answer sorry alot sorry