Question

The altitude of a triangle,whose area is 42cm² and base is 12cm,is ?​

Answer 1

Answer:

Lets take altitude as A,

Area of the triangle = 42cm^2

1/2×B×A = 42cm^2

1/2×12×A = 42

6×A = 42

A = 42/6

A = 8cm

Therefore, altitude is = 8cm

Answer 2

Step-by-step explanation:

• area
• $= 42(cm}^{2}$
• area of triangle
• $1 \div 2 \times base \: \times height$
• now base
• $12 cm$
• height equal to
• $1 \div 2 \times12 \times height$
• height
• $= 7cm$