The altitude of a triangle whose area is 45m square and corresponding base is 15 m is
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Answer:
6 cm.
Step-by-step explanation:
Given area of triangle=45 sq m
And base = 15 cm
Let length of altitude be h
Now ,
area of triangle= 1/2 × base × altitude
45=1/2×15×h
h=( 45×2)/15
h=6 cm
Therefore altitude= 6 cm
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