Math, asked by snehalchavan4604, 3 months ago

The altitude of a triangle whose area is 45m square and corresponding base is 15 m is

Answers

Answered by d200876
1

Answer:

6 cm.

Step-by-step explanation:

Given area of triangle=45 sq m

And base = 15 cm

Let length of altitude be h

Now ,

area of triangle= 1/2 × base × altitude

45=1/2×15×h

h=( 45×2)/15

h=6 cm

Therefore altitude= 6 cm

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