Question

The altitude of a triangle whose area is 96 sq cm and base is 16 cm is​

Answer 1

Thanks for your question...

Your required answer :

Given :

• Area = 96 cm²
• Base = 16 cm

To find :

• Height / Altitude

We know that Area of triangle : 1/2 × b × h

Solution :

$\frac{1}{2} \times 16 \times h = 96 \\ \\ 8h = 96 \\ \\ h = \frac{96}{8} \\ \\ h = 12 \: cm$

Therefore height / altitude of given triangle is 12 cm.

Brainliest Please

Answer 2

Answer:

Hence the value of altitude of triangle is 12 cm.

Step-by-step explanation:

As per the data provided in the given question.

The given data is as follows,

Area of a triangle (A) is 96 sq. cm.

And base (b) is 16 cm.

We have to find the value of altitude of triangle i.e. (hb).

Here we will be using the formula of altitude of triangle.

$hb=2\times\frac{A}{b}$

Now we will substitute the given values in above formula.

Further, we get

$hb=2\times\frac{96}{16}$

We will divide 16 by 2 get 8.

$=\frac{96}{8}$

Now we will divide the above term by 4

Further, we get

$=\frac{24}{2}$

Now we will divide 24 by 2 .

We get,

$=12\;cm$

Hence the value of altitude of triangle is 12 cm.