Question

The altitude of parallelogram corresponding to base of length 15cm is 18cm. Find the area of parallelogram.
Pls answer fast
Who ever will answer I will mark his or her's answer as brainlist.
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Answer 1

Answer:

The Altitude (height) of parallelogram is 15cm ...

Base of parallelogram is 18 cm...

Step-by-step explanation:✏✏✏✏

area of ll gm = base × height

→15 × 18 cm²

→ 270 cm ²

Answer 2

$\bold{\underline{\underline{\huge{\rm{AnsWer:}}}}}$

Area of parallelogram = 270 cm²

$\bold{\underline{\underline{\large{\rm{StEp\:by\:stEp\:explanation:}}}}}$

GiVeN :

• Base of the parallelogram = 15 cm
• Altitude of the parallelogram = 18 cm

To FiNd :

• Area of the parallelogram

SoLuTioN :

We have the base and altitude (height) of the parallelogram. We can thereby simply calculate the area using the formula.

FoRmUlA :

$\bold{\large{\boxed{\tt{\green{Area\:of\:parallelogram\:=\:base\:\times\:height}}}}}$

Block in the values,

$\hookrightarrow$ $\tt{15\:\times\:18}$

$\hookrightarrow$ $\tt{270}$

$\bold{\large{\therefore{\purple{\boxed{\rm{Area\:of\:parallelogram\:=\:270\:cm^2}}}}}}$

$\bold{\huge{\tt{\underline{VeRiFiCaTiOn}}}}$

To verify the answer, block in all the available data in the formula of area of the parallelogram. Try equating the LHS to the RHS or vice versa.

Data :

• Area of the parallelogram = 270 cm²
• Base = 15 cm
• Height = 18 cm

Block in the values in the formula,

$\hookrightarrow$ $\tt{270\:=\:15\:\times\:18}$

$\hookrightarrow$ $\tt{\dfrac{270}{15}=\:18}$

$\hookrightarrow$ $\tt{18\:=\:18}$

LHS = RHS

Verified.