the altitude of right triangle is 7cm Less than the base x and the hypotenuse is 13cm. find the quadratic representation of this situation..
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By using Pythagoras formula,
(H^2) = (B^2) + (A^2)
(13)2 = (x)2 + (x-7)2
169 = x^2 + x^2 + 49 -14x
2x^2 -14x = 169-49
2{x^2 -7x} = 120
x^2 - 7x = 120/2
x^2 - 7x = 60
x^2 - 7x - 60 = 0
x^2 - 12x + 5x - 60 = 0
X(x - 12) + 5 (x- 12) = 0
(X -12) (x +5) = 0
Therefore, x = 12 & -5
As measurement can't be negative
So, The base is 12cm and altitude is 12-7 = 5cm.
Hope it will help you.
(H^2) = (B^2) + (A^2)
(13)2 = (x)2 + (x-7)2
169 = x^2 + x^2 + 49 -14x
2x^2 -14x = 169-49
2{x^2 -7x} = 120
x^2 - 7x = 120/2
x^2 - 7x = 60
x^2 - 7x - 60 = 0
x^2 - 12x + 5x - 60 = 0
X(x - 12) + 5 (x- 12) = 0
(X -12) (x +5) = 0
Therefore, x = 12 & -5
As measurement can't be negative
So, The base is 12cm and altitude is 12-7 = 5cm.
Hope it will help you.
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