The altitude to the side of AB and AD of parallelogram ABCD are 5cm and 20cm respectively. If the area of the parallelogram is 160 sq.cm,find its perimeter
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Perimeter=80 cm.
Step-by-step explanation:
Given:
Area of parallelogram ABCD=160 sq cm
As shown in the figure below, let DL=5cm, BM=20 cm
We know that area parallelogram ABCD=
⇒
⇒
⇒AB=32 cm
Also area of parallelogram ABCD=
⇒160=[tex]20\times AD[/tex]
⇒AD=8 cm.
We know that perimeter of parallelogram ABCD=2(AB+AD)
=2(32+8)
=80 cm
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