The altitudeand base of a triangle having area 600sq. Cmare in the ratio25:3.find altitude and base
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Answered by
1
let the altitude and base be 25x cm and 3x cm.
so area=1/2×b×a=600
1/2×25x×3x=600
75x^2=1200
x^2=16
x=4cm.
so altitude=4×25=100cm.
base=4×3=12cm
so area=1/2×b×a=600
1/2×25x×3x=600
75x^2=1200
x^2=16
x=4cm.
so altitude=4×25=100cm.
base=4×3=12cm
Answered by
0
600 = 1/2 x base x altitude or height
600 = 1/2 x 3x x 25x
600 = 1/2 x 75x^2
600 x 2 = 75x^2
1200 = 75x^2
1200/75 = x^2
16 = x^2
x = √16
x = 4
600 = 1/2 x 3x x 25x
600 = 1/2 x 75x^2
600 x 2 = 75x^2
1200 = 75x^2
1200/75 = x^2
16 = x^2
x = √16
x = 4
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