The altitudes AD , BE & CF of triangle ABC are equal .Show that the measure of each angle of triangle ABC is 60 degree
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In right-angle triangles BCE and CBF, we have,
BC = BC (common hypotenuse);
BE = CF (given).
Hence BCF and CBF are congruent, by RHS theorem. Comparing the triangles, we get \angle B = \angle C∠B=∠C.
This implies that
AC = AB (sides opposite to equal angles).
Similarly,
AD = BE \Rightarrow \angle B = \angle AAD=BE⇒∠B=∠A
\Rightarrow AC = BC⇒AC=BC
Together, we get AB = BC = ACAB=BC=ACor \triangle ABC△ABC is equilateral. [hence \quad proved][henceproved]
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