The AM of 20 observations was obtained as 150. Later it was found that
two observations 15 and 18 were wrongly recorded as 50 and 80 respectively .
Find the corrected AM.
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Mean of 20 observations = M = (Sum Total of the 20 observations)/ 50 ( Total number of observations) = 150
Therefore, the total sum = 20*150= 3000.
Subtracting 50 & 80(which was wrongly recorded)
3000 - 50 - 80 = 3870
Adding 15 & 18 ( which is to be included)
3870 +18 + 15 = 3903
Therefore, now the total sum of the 20 observations is 3903
Hence, the required mean is 3903/20
= 195.15
Thus ,the mean is 195.15
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0
Answer:
The corrected mean is 245.15.
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