Question

The am of first n natural number is 6 the value of n is

Answer 1

Step-by-step explanation:

am of 1st n natural no. =

n+1/2/n =6

n(n+1)/2=6

n^2+n=12

n^2+n-12=0

n(n-3)+4(n-3)=0

So n will be 3 or -4

but n is natural no So it must be n=3