the am of two numbers A and B exceeds their GM by 40 and their hm is 36 the value of A and B are
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Answer:
A*B= 40*36this is my answer
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Step-by-step explanation:
We have A−G=1.5 and G−H=1.2
Also we now H=AG2
Thus, we get G−AG2=1.2
⇒AG(A−G)=1.2
⇒5G=4A and also A−G=1.5
∴A=7.5,G=6
Hence we get the numbers to be 12,3
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